Lab 5

I realized that the pictures I took in class were too shaky and only showed either the just input or just the output (for the inverting and non-inverting amplifiers). Instead I used the video of turning the potentiometer to show the input and output. When the potentiometer is at minimum resistance, it shows the output is twice the amplitude of the input.

Vout = Vin * (1 + R2/R1)

.2V=9V(1+R2/10,000)

2,000=9V(1+R2)

222.222=1+R2

R2=221.22–> 220 ohms

This video shows the potentiometer turning from minimum to maximum resistance. Since a potentiometer has a resistance of 10,000 ohms, the calculations are the same for the first video.

Vout = Vin * (1 + R2/R1)

.2V=9V(1+R2/10,000)

2,000=9V(1+R2)

222.222=1+R2

R2=221.22–> 220 ohms

Vout = -Vin*(Rf/Rin)

.2V=-9V(Rf/10,000)

-.022=Rf/10,000

-222.22=Rf–> -220 ohms

What we are seeing is different from the non-inverting amplifier because the inverting amplifier inverts the output to be a negative sine wave with a gain of 2 rather than a positive sine wave with a gain of 2.

Vout = -Vin*(Rf/Rin)

.2V=-9V(10,000/Rin)

-.022=(10,000/Rin)

-.022(Rin)=10,000

Rin= -454,545.455–> -470,000 ohms